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The correct answer is  C, 71 cy., " "2. True False n X X 0( X 0 2. 2.RINCORRECT! The correct answer is  False. ,  3.54 cy 78 cy 92 cy 133 cyn3. 3.XINCORRECT! The correct answer is  B, 78 cy., " "4. True False n X 0X 0 4. 4.PINCORRECT! The correct answer is  True. ,  5.Not worry about wind as it will help to cool the concrete surface. Assure that the curing water is as cold as possible. Take appropriate steps to lower the mix temperature when it approaches 90F. Use clear/white plastic as part of the cure process. n(5. 5.INCORRECT! The correct answer is  D, use clear/white plastic as part of the cure process., P P6. True False n X 0X 0 6. 6.PINCORRECT! The correct answer is  True. ,  7.zMust be near the surface to reduce deflection. Must start out on firm but yielding material. Is of no particular importance in the bridge s stability. Relies on structural design, not mass.n7. 7.INCORRECT! The correct answer is  D, relies on structural design, not mass. , C C8.ZNeed not be concerned with levelness of materials encountered at the bottom of seal excavation. Should never feel responsible for monitoring the positioning of the internal supports for the sheet pile walls. Should arbitrarily lessen the seal depth if hard rock is encountered while excavating for the bottom of seal elevation. None of the above. [ n([8. 8.rINCORRECT! The correct answer is  D, none of the above. , / /9.Is critical to a bridge s load bearing strength. Must be closely checked for specified lap splice lengths, support and wire tie accuracy. Must be closely checked for size, shape, length, spacing and quantity used. All of the above. 0nZ(9. 9.pINCORRECT! The correct answer is  D, all of the above. , . .10. True False n J X 0L X 0 10. 10.RINCORRECT! The correct answer is  False. ,  11.&1/3 turn 1/2 turn 2/3 turn 1 full turn'n'11. 11.`INCORRECT! The correct answer is  B, 1/2 turn. , & &12.86 12 18 None of the aboven12. 12.rINCORRECT! The correct answer is  D, none of the above. , / /13.2 2 3 4 n13. 13.`INCORRECT! The correct answer is  A, 2 inches. , & &14.5 6 7 9n14. 14.RINCORRECT! The correct answer is  C, 7. ,  15. 103.4% 107.3%n15. 15.\INCORRECT! The correct answer is  C, 109.4%. 0 $ $/P   0` fy`ff3` Mj*333FV*` ffNNt^X` ffNL|>rL` +T3f3f` MMMff3f` Lx[he2` {$$` +T3f3f` +T3f3f33>?" dd@f?nA33d@f   33@ ` 33 n?" dd@   @@``PR    @ ` ` p>>L0  4s(  4 4 0G  #" ` ` G  T Click to edit Master title style! !$ 4 0G  "p ` G  RClick to edit Master text styles Second level Third level Fourth level Fifth level!     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S  6\G  _P  G  P*    6Q  _  G  R*  H  0޽h ? 3380___PPT10.)#  8(    0@  P     >*   0!       @*   6%  _P    >*   6+  _    @* H  0޽h ? 3380___PPT10.,| 0L0 {s   (  x  c $6 8    x  c $6 80 0    F 0   0   6: 0 @X 0 Next . 233X 0`   033p`H  0޽h ? 33___PPT10i.zcB+D='  = @B +  0L0 ` p(     } 0e0e 43"0e``     s GG 0e0e 4#" 0eP    "p`Pp  N ?"6@`NNN?N  X 0  N ?"6@`NNN?N   X 0  N ?"6@`NNN?N0 P  X 0   N ?"6@`NNN?NP p  X 0   Hs ?"6@ NNN?N` An 8 ft. diameter drilled shaft has a tip elevation of 197 ft. With a top elevation of 235 ft., what is the theoretical quantity of concrete for this shaft? 2fH  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0 0  ](       40e0e 43"0e``      H ?"6@ NNN?N` An 8 ft. diameter drilled shaft has a tip elevation of 197 ft. With a top elevation of 235 ft., what is the theoretical quantity of concrete for this shaft? 2f   6p?P  DCORRECT! 2  F 0   0   60 o X 0 Next . 233X 0`   033p`H   0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0 @ C(     m 0e0e 43"0e``     H ?"6@ NNN?N` An 8 ft. diameter drilled shaft has a tip elevation of 197 ft. With a top elevation of 235 ft., what is the theoretical quantity of concrete for this shaft? 2f   <|m  4P0`  m  F 0  0  6t0 x X 0 Next . 233X 0`  033p`H  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0 P  {(     0e0e 43"0e``     H ?"6@ NNN?N` Air entrained concrete is highly resistant to the destructive effects of freeze-thaw cycling due to the presence of large air bubbles in the paste. 2f   B 4E0   "p`PpH  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0 `  T(     d 0e0e 43"0e``     H  ?"6@ NNN?N` Air entrained concrete is highly resistant to the destructive effects of freeze-thaw cycling due to the presence of large air bubbles in the paste. 2f  6Њ ?P  DCORRECT! 2  F 0  0  6 0 a X 0 Next . 233X 0`   033p`H  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0 p  :(     쓋 0e0e 43"0e``     H8  ?"6@ NNN?N` Air entrained concrete is highly resistant to the destructive effects of freeze-thaw cycling due to the presence of large air bubbles in the paste. 2f  <  4P0`    F 0   0   6d 0 f X 0 Next . 233X 0`   033p`H  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +!   0L0    (        0e0e 43"0e``      s ܴ 0e0e 4#" 0eP@   "p`Pp   N ?"6@`NNN?N0   6 X 0   N ?"6@`NNN?NP @  B X 0   N ?"6@`NNN?Np   > X 0   N ?"6@`NNN?N   F X 0   HD  ?"6@ NNN?N`| A footing is 8 ft. wide by 13 ft. long. The bottom of the footing is at elevation 211.00 and the original ground is at elevation 225.00. The finish grade of the deck is 235.00. What is the amount of structure excavation? 2fH   0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0   $(  $ $   ċ 0e0e 43"0e``    $ Hȋ  ?"6@ NNN?N`| A footing is 8 ft. wide by 13 ft. long. The bottom of the footing is at elevation 211.00 and the original ground is at elevation 225.00. The finish grade of the deck is 235.00. What is the amount of structure excavation? 2f  $ 6 ϋ ?s P  DCORRECT! 2  F 0 $ 0 $ 6ԋ 0  X 0 Next . 233X 0` $ 033p`H $ 0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0  ((  ( (  hڋ 0e0e 43"0e``    ( Hۋ  ?"6@ NNN?N`| A footing is 8 ft. wide by 13 ft. long. The bottom of the footing is at elevation 211.00 and the original ground is at elevation 225.00. The finish grade of the deck is 235.00. What is the amount of structure excavation? 2f  ( <  4 0   F 0 ( 0 ( 6 0  X 0 Next . 233X 0` ( 033p`H ( 0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0  ,#(  , ,   0e0e 43"0e``   + , H  ?"6@ NNN?N` u;The vibrator should not be used to move concrete laterally.< 2<f , B  4`0    "p`PpH , 0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +m  0L0 ld  0(  0 0   0e0e 43"0e``   + 0 Hp  ?"6@ NNN?N` u;The vibrator should not be used to move concrete laterally.< 2<f 0 6p ?P- DCORRECT! 2  F 0  0 0  0 6Hp 0  X 0 Next . 233X 0`  0 033p`H 0 0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +S  0L0 RJ  4(  4 4  p 0e0e 43"0e``  p  + 4 HPp  ?"6@ NNN?N` u;The vibrator should not be used to move concrete laterally.< 2<f 4 <\p  400@  p  F 0  4 0  4 6p 0  X 0 Next . 233X 0`  4 033p`H 4 0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0 w 8(  8 8  T p 0e0e 43"0e``  p   8 s `p 0e0e 4#" 0ePP  p  "p`Pp 8 N ?"6@`NNN?N @  X 0 8 N ?"6@`NNN?N  X 0 8 N ?"6@`NNN?N0    X 0 8 N ?"6@`NNN?N 0  X 0+ 8 H)p  ?"6@ NNN?N` u;During hot weather concrete placement, the inspector should< 2<fH 8 0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +m  0L0 ld <(  < <  >p 0e0e 43"0e``  p  + < H8Ap  ?"6@ NNN?N` u;During hot weather concrete placement, the inspector should< 2<f  < 6xCp ?P- DCORRECT! 2  F 0 < 0 < 6Ip 0  X 0 Next . 233X 0` < 033p`H < 0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +S  0L0 RJ @(  @ @  Lό0e0e 43"0e``  p  + @ HPp  ?"6@ NNN?N` u;During hot weather concrete placement, the inspector should< 2<f  @ <Rp  40  p  F 0 @ 0 @ 6PWp 0  X 0 Next . 233X 0` @ 033p`H @ 0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0  D8(  D D  |`p 0e0e 43"0e``  p  @ D Hap  ?"6@ NNN?N`p  PFor footings and seals, the bottom elevation shown on the plans serves as the lower pay limit. Should the contractor over excavate below that limit or should the need arise to excavate below that limit to attain the necessary bearing value, the situation must be corrected in a manner that the construction Project Manager must approve.Q 2Qf D B@np  4 0p p  "p`PpH D 0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0 y  H(  H H  Xup 0e0e 43"0e``  p  @ H HDwp  ?"6@ NNN?N`p  PFor footings and seals, the bottom elevation shown on the plans serves as the lower pay limit. Should the contractor over excavate below that limit or should the need arise to excavate below that limit to attain the necessary bearing value, the situation must be corrected in a manner that the construction Project Manager must approve.Q 2Qf H 6   0L0 =5 (     D' 0e0e 43"0e``     H|(  ?"6@ NNN?N`0_  `Your bridge has precast bulb-I girders with a camber of 2 and the deck and rail deadload together has a deflection of 2 . The top flange of the bulb-I girders is a total of 2 feet wide and your superelvation is 0.04 ft/ft. With a minimum buildup required across the entire girder of 1 , then the total buildup at the ends of the beams at the girder centerline will be ______.z 2zf,Rj    <P+  4P 0   F 0  0  6* 0 X 0 Next . 233X 0`  033p`H  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +   0L0  t(     < 0e0e 43"0e``     s  0e0e 4#" 0eP   "p`Pp  N ?"6@`NNN?N   ]X 0  N ?"6@`NNN?N   aX 0  N ?"6@`NNN?N@ `  eX 0  N ?"6@`NNN?N`   iX 0  H@  ?"6@ NNN?N`0| You have a 6 ft. diameter drilled shaft with a clearance of 3 from the reinforcement cage to the side of the shaft. How many spacers are required at each interval around the drilled shaft reinforcement cage? 2fH  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0  a(     J 0e0e 43"0e``     HPP  ?"6@ NNN?N`0| You have a 6 ft. diameter drilled shaft with a clearance of 3 from the reinforcement cage to the side of the shaft. How many spacers are required at each interval around the drilled shaft reinforcement cage? 2f   6HU ? P  DCORRECT! 2  F 0  0  6\[ 0 $X 0 Next . 233X 0`  033p`H  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0  G(     PM 0e0e 43"0e``     H`  ?"6@ NNN?N`0| You have a 6 ft. diameter drilled shaft with a clearance of 3 from the reinforcement cage to the side of the shaft. How many spacers are required at each interval around the drilled shaft reinforcement cage? 2f   <f  4` 0    F 0  0  6i 0 )X 0 Next . 233X 0`  033p`H  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +Z  0L0 YQ (    6Pq   pH@8___PPT9  e 109.4% 121.5%n %m    z 0e0e 43"0e``     s Ā 0e0e 4#" 0e 0P p   * kK  N ?"6@`NNN?N `  mX 0  N ?"6@`NNN?N    X 0  N ?"6@`NNN?N  @ " X 0  N ?"6@`NNN?N  qX 0  Hԅ  ?"6@ NNN?N`0 You have a post-tensioned box girder bridge that will have the tendons tensioned from both ends. Given the following elongation amounts, what is the % of elongation per tendon? 2f2l k   #"000k   TȌ 33ff?"6@ NNN?Np   L5  @`5  T 33ff?"6@ NNN?N p  k6 7/84 @`  T 33ff?"6@ NNN?N   I0 @`  Tج 33ff?"6@ NNN?N   PBent 4 @`  T䴶 ff?"6@ NNN?Np  M54  @`  T< ff?"6@ NNN?N p  M65  @`  TP ff?"6@ NNN?N  L7  @`  T϶ ff?"6@ NNN?N  PBent 1 @`-   Tٶ 33ff?"6@ NNN?Npk cCalculated 80% Elongation @`*   T 33ff?"6@ NNN?N kp `100% Actual Elongation @`)   T 33ff?"6@ NNN?Nk  _20% Actual Elongation @`    T4 33ff?"6@ NNN?Nk B @`B  Z33ff1 ?"0@NNN?NkkB  Z33ff1 ?"0@NNN?N  B  Z33ff1 ?"0@NNN?Nk B  Z33ff1 ?"0@NNN?Nk B B T33ff1 ?"0@NNN?Nk B C T33ff1 ?"0@NNN?N k  B D T33ff1 ?"0@NNN?Npkp B E T33ff1 ?"0@NNN?NB L T33ff1 ?"0@NNN?N  H  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +   0L0  )(     ڶ 0e0e 43"0e``     H  ?"6@ NNN?N`0 You have a post-tensioned box girder bridge that will have the tendons tensioned from both ends. Given the following elongation amounts, what is the % of elongation per tendon? 2f6l k  ) #"000k    T 33ff?"6@ NNN?Np   K5  @`=   T 33ff?"6@ NNN?N p  s6 7/8< @`   T 33ff?"6@ NNN?N   I0 @`   T\& 33ff?"6@ NNN?N   PBent 4 @`  T ff?"6@ NNN?Np  L54  @`  T7 ff?"6@ NNN?N p  L65  @`  T@ ff?"6@ NNN?N  K7  @`  T$I ff?"6@ NNN?N  PBent 1 @`-  TR 33ff?"6@ NNN?Npk cCalculated 80% Elongation @`*  T[ 33ff?"6@ NNN?N kp `100% Actual Elongation @`)  Ttd 33ff?"6@ NNN?Nk  _20% Actual Elongation @`   Tm 33ff?"6@ NNN?Nk B @`B  Z33ff1 ?"0@NNN?NkkB  Z33ff1 ?"0@NNN?N  B  Z33ff1 ?"0@NNN?Nk B  Z33ff1 ?"0@NNN?Nk B  T33ff1 ?"0@NNN?Nk B  T33ff1 ?"0@NNN?N k  B  T33ff1 ?"0@NNN?Npkp B  T33ff1 ?"0@NNN?NB  T33ff1 ?"0@NNN?N   ! 6q ?C P  DCORRECT! 2  F 0 % 0 & 6x 0 2X 0 Next . 233X 0` ' 033p`H  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0L0  *(     } 0e0e 43"0e``     H8  ?"6@ NNN?N`0 You have a post-tensioned box girder bridge that will have the tendons tensioned from both ends. Given the following elongation amounts, what is the % of elongation per tendon? 2f6l k  * #"000k    T 33ff?"6@ NNN?Np   K5  @`=   T@ 33ff?"6@ NNN?N p  s6 7/8< @`   T0 33ff?"6@ NNN?N   I0 @`   T0 33ff?"6@ NNN?N   PBent 4 @`  T ff?"6@ NNN?Np  L54  @`  T ff?"6@ NNN?N p  L65  @`  T ff?"6@ NNN?N  K7  @`  Tɸ ff?"6@ NNN?N  PBent 1 @`-  TҸ 33ff?"6@ NNN?Npk cCalculated 80% Elongation @`*  Ttܸ 33ff?"6@ NNN?N kp `100% Actual Elongation @`)  T|ָ 33ff?"6@ NNN?Nk  _20% Actual Elongation @`   T 33ff?"6@ NNN?Nk B @`B  Z33ff1 ?"0@NNN?NkkB  Z33ff1 ?"0@NNN?N  B  Z33ff1 ?"0@NNN?Nk B  Z33ff1 ?"0@NNN?Nk B  T33ff1 ?"0@NNN?Nk B  T33ff1 ?"0@NNN?N k  B  T33ff1 ?"0@NNN?Npkp B  T33ff1 ?"0@NNN?NB  T33ff1 ?"0@NNN?N   " <  4 0@   F 0 & 0 ' 6 0 7X 0 Next . 233X 0` ( 033p`H  0޽h ? 3fffff3̙3f̙___PPT10i.zhY+D='  = @B +  0  (  X  C      S ^  0    H  0޽h ? 3380___PPT10.)r rhw Xkc0hnQ'גW.V. K%'-3 9J@ZG@PW]kflis~:mGi1Oh+'0 hp  GENERAL INSPECTOR Lori Butlerhwym06b42Microsoft Office PowerPoint@Y:@pc2Iz@PzKGhg  ,V'&" WMFC@ <8?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~      !"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~      Root EntrydO)PicturestPCurrent UserSummaryInformation(PowerPoint Document(DocumentSummaryInformation8